Class 6: Quantifiers and More
Schedule
Everyone should have received their graded PS1 by now. Please read the comments posted in collab.
Problem Set 2 is due Friday at 6:29pm.
You should finish reading MCS Chapter 3 by Tuesday (12 September).
Links
If you believe real computing systems have the property that the values you read from memory will match what you wrote there, see:
Sudhakar Govindavajhala and Andrew W. Appel. Using Memory Errors to Attack a Virtual Machine, IEEE Symposium on Security and Privacy 2003.
Bianca Schroeder, Eduardo Pinheiro, Wolf-Dietrich Weber. DRAM Errors in the Wild: A Large-Scale Field Study. SIGMETRICS 2009.
Kaveh Razavi, Ben Gras, Erik Bosman, Bart Preneel, Cristiano Giuffrida and Herbert Bos. Flip Feng Shui: Hammering a Needle in the Software Stack. USENIX Security 2016.
Yuan Xiao, Xiaokuan Zhang, Yinqian Zhang, and Radu Teodorescu. One Bit Flips, One Cloud Flops: Cross-VM Row Hammer Attacks and Privilege Escalation, USENIX Security 2016.
Sahand Saba’s Understanding SAT by Implementing a Simple SAT Solver in Python [Code with Dave’s modifications: https://github.com/evansuva/simple-sat]
Millennium Problems on Clay institute’s
website. Whether or not we can
solve the satisfiability of a given CNF or 3CNF formula in polynomial time,
is the P vs. NP question in this list.
Programs and Proofs
What does it mean to test a computing system? What does it mean for a computing system to always behave correctly?
Can a mathematical proof guarantee a real computing system will behave correctly?
Minima
The minimum of a set with respect to some comparator operator is the element which is “less than” (according to that comparator) every other element: $m \in S$ is the minimum of $S$ if and only if $\forall x \in S - { m } . m \prec x$.
$$ \forall S \in \textrm{pow}(\mathbb{N}) - { \varnothing } \ldotp \exists m \in S\ldotp \forall x \in S - {m}\ldotp m < x $$
Formulas, Propositions, and Inference Rules
$P \implies Q$ is a formula.
$\forall P \in { T, F } . \forall Q \in { T, F } . P \implies Q$ is a proposition.
$\infer{Q}{P}$ is an inference rule.
A formula is satisfiable if there is some way to make it true.
$P \implies Q$ is satisfiable:
$\exists P \in { T, F } . \exists Q \in {T, F } . P \implies Q$
We can show a formula is satisfiable by giving one choice for the variable assignments that makes it true. For example, $P = T$, $Q = T$.
A formula is valid if there is no way to make it false.
$P \implies Q$ is not valid:
$\forall P \in { T, F } . \forall Q \in {T, F } . P \implies Q$
This proposition is false, we can chose $P = T$, $Q = F$.
An inference rule is sound if it never leads to a false conclusion. An inference rule $\infer{Q}{P}$ is sound if and only if the formula $P \implies Q$ is valid. So, this way, we can find out whether an inference rule is sound or not, by checking out whether the corresponding formula is valid or not.
Negating Quantifiers
What is the negation of $\forall x \in S . P(x)$?
What is the negation of $\exists x \in S . P(x)$?
Satisfiability
Definition. A formula is in SAT if it is in CNF form and it is satisfiable.
Definition. A formula is in 3SAT if it is in 3CNF form and it is satisfiable.
$$ (x_1 \vee x_2 \vee x_3) \wedge (x_1 \vee \overline{x_2} \vee x_3) \wedge (\overline{x_1} \vee x_2 \vee \overline{x_3}) $$
\begin{center} \tiny \begin{math} (x{48} \vee x{4} \vee \overline{x{9}}) \wedge (\overline{x{44}} \vee x{50} \vee \overline{x{37}}) \wedge (\overline{x{8}} \vee \overline{x{1}} \vee x{28}) \wedge (x{21} \vee x{27} \vee \overline{x{32}}) \wedge (x{17} \vee x{29} \vee \overline{x{30}}) \wedge (x{30} \vee x{24} \vee x{37}) \wedge (\overline{x{22}} \vee \overline{x{27}} \vee \overline{x{44}}) \wedge (x{8} \vee \overline{x{25}} \vee \overline{x{24}}) \wedge (\overline{x{44}} \vee x{50} \vee x{14}) \wedge (x{45} \vee x{15} \vee x{37}) \wedge (\overline{x{16}} \vee x{14} \vee \overline{x{36}}) \wedge (\overline{x{33}} \vee x{5} \vee x{26}) \wedge (x{18} \vee \overline{x{7}} \vee \overline{x{24}}) \wedge (x{31} \vee x{38} \vee x{28}) \wedge (x{31} \vee \overline{x{33}} \vee \overline{x{8}}) \wedge (x{49} \vee x{7} \vee \overline{x{6}}) \wedge (x{34} \vee \overline{x{8}} \vee x{46}) \wedge (x{4} \vee \overline{x{5}} \vee \overline{x{35}}) \wedge (x{43} \vee x{27} \vee x{39}) \wedge (\overline{x{46}} \vee \overline{x{40}} \vee \overline{x{27}}) \wedge (\overline{x{25}} \vee x{14} \vee \overline{x{49}}) \wedge (x{38} \vee x{5} \vee x{15}) \wedge (x{9} \vee x{14} \vee \overline{x{19}}) \wedge (x{45} \vee \overline{x{42}} \vee \overline{x{39}}) \wedge (x{34} \vee \overline{x{22}} \vee \overline{x{28}}) \wedge (\overline{x{20}} \vee x{15} \vee \overline{x{8}}) \wedge (\overline{x{44}} \vee \overline{x{10}} \vee \overline{x{9}}) \wedge (x{22} \vee \overline{x{31}} \vee x{14}) \wedge (\overline{x{9}} \vee \overline{x{42}} \vee \overline{x{15}}) \wedge (\overline{x{40}} \vee x{12} \vee \overline{x{32}}) \wedge (\overline{x{20}} \vee \overline{x{6}} \vee \overline{x{15}}) \wedge (\overline{x{37}} \vee x{39} \vee \overline{x{23}}) \wedge (\overline{x{3}} \vee \overline{x{40}} \vee \overline{x{32}}) \wedge (\overline{x{4}} \vee \overline{x{25}} \vee x{7}) \wedge (\overline{x{20}} \vee \overline{x{36}} \vee \overline{x{37}}) \wedge (\overline{x{40}} \vee \overline{x{35}} \vee x{39}) \wedge (\overline{x{43}} \vee \overline{x{40}} \vee \overline{x{7}}) \wedge (x{34} \vee x{44} \vee x{26}) \wedge (x{13} \vee x{27} \vee x{28}) \wedge (x{12} \vee \overline{x{36}} \vee x{7}) \wedge (\overline{x{16}} \vee x{9} \vee \overline{x{24}}) \wedge (\overline{x{48}} \vee x{14} \vee x{28}) \wedge (x{16} \vee x{4} \vee x{40}) \wedge (\overline{x{25}} \vee x{15} \vee x{37}) \wedge (x{47} \vee \overline{x{26}} \vee \overline{x{23}}) \wedge (x{4} \vee \overline{x{13}} \vee x{36}) \wedge (x{48} \vee \overline{x{13}} \vee \overline{x{37}}) \wedge (x{4} \vee x{35} \vee \overline{x{27}}) \wedge (\overline{x{22}} \vee x{47} \vee x{26}) \wedge (\overline{x{22}} \vee \overline{x{46}} \vee x{27}) \wedge (\overline{x{20}} \vee x{49} \vee x{11}) \wedge (x{42} \vee \overline{x{10}} \vee x{28}) \wedge (\overline{x{45}} \vee x{28} \vee \overline{x{37}}) \wedge (x{14} \vee \overline{x{32}} \vee \overline{x{23}}) \wedge (x{22} \vee x{14} \vee x{23}) \wedge (\overline{x{17}} \vee \overline{x{46}} \vee \overline{x{7}}) \wedge (\overline{x{31}} \vee x{46} \vee \overline{x{50}}) \wedge (x{34} \vee \overline{x{41}} \vee x{43}) \wedge (x{17} \vee \overline{x{9}} \vee x{15}) \wedge (x{46} \vee x{14} \vee \overline{x{12}}) \wedge (\overline{x{20}} \vee x{12} \vee x{14}) \wedge (x{41} \vee x{42} \vee \overline{x{15}}) \wedge (x{48} \vee x{46} \vee \overline{x{36}}) \wedge (\overline{x{22}} \vee \overline{x{4}} \vee \overline{x{49}}) \wedge (x{22} \vee x{12} \vee \overline{x{42}}) \wedge (x{13} \vee \overline{x{38}} \vee x{39}) \wedge (x{48} \vee \overline{x{16}} \vee \overline{x{27}}) \wedge (x{17} \vee \overline{x{18}} \vee \overline{x{26}}) \wedge (x{48} \vee \overline{x{40}} \vee \overline{x{35}}) \wedge (\overline{x{43}} \vee \overline{x{40}} \vee \overline{x{49}}) \wedge (x{29} \vee x{11} \vee \overline{x{32}}) \wedge (x{33} \vee \overline{x{17}} \vee x{39}) \wedge (\overline{x{25}} \vee \overline{x{9}} \vee \overline{x{6}}) \wedge (x{40} \vee \overline{x{50}} \vee x{19}) \wedge (x{8} \vee x{10} \vee \overline{x{27}}) \wedge (x{5} \vee x{9} \vee \overline{x{26}}) \wedge (x{45} \vee \overline{x{38}} \vee \overline{x{27}}) \wedge (\overline{x{4}} \vee \overline{x{40}} \vee \overline{x{42}}) \wedge (x{21} \vee x{50} \vee x{12}) \wedge (\overline{x{8}} \vee \overline{x{14}} \vee \overline{x{42}}) \wedge (\overline{x{17}} \vee x{47} \vee \overline{x{27}}) \wedge (x{49} \vee \overline{x{12}} \vee \overline{x{6}}) \wedge (x{27} \vee x{49} \vee \overline{x{32}}) \wedge (\overline{x{29}} \vee \overline{x{12}} \vee \overline{x{26}}) \wedge (x{48} \vee \overline{x{2}} \vee x{6}) \wedge (x{16} \vee x{36} \vee x{49}) \wedge (x{33} \vee \overline{x{12}} \vee \overline{x{26}}) \wedge (\overline{x{33}} \vee x{29} \vee x{49}) \wedge (\overline{x{48}} \vee x{2} \vee x{19}) \wedge (x{25} \vee x{36} \vee x{49}) \wedge (x{21} \vee x{40} \vee \overline{x{14}}) \wedge (\overline{x{34}} \vee \overline{x{44}} \vee \overline{x{6}}) \wedge (x{48} \vee \overline{x{50}} \vee \overline{x{1}}) \wedge (x{5} \vee \overline{x{12}} \vee x{7}) \wedge (x{21} \vee \overline{x{35}} \vee \overline{x{27}}) \wedge (\overline{x{22}} \vee \overline{x{16}} \vee \overline{x{14}}) \wedge (\overline{x{13}} \vee \overline{x{35}} \vee \overline{x{12}}) \wedge (\overline{x{4}} \vee \overline{x{35}} \vee \overline{x{42}}) \wedge (\overline{x{50}} \vee \overline{x{40}} \vee x{7}) \wedge (x{25} \vee x{47} \vee \overline{x{12}}) \end{math} \end{center}
Converting Truth Tables to DNF
\begin{tabular}{cc|cc}
$P$ & $Q$ & $P \implies Q$ & $P \oplus Q$ \ \hline
\T & \T & \T & \F
\T & \F & \F & \T
\F & \T & \T & \T
\F & \F & \T & \F
\end{tabular}
The output of the operator is \T\ if and only if the inputs do match one row where the output is \T. So, to get a DNF we can go over all the rows where hte output is \T, and for each write a clause that means we are in that row. Then we OR all such (conjunctive) clauses. For example, for $P \oplus Q$ we get
$$(P \wedge \neg Q) \vee (\neg P \wedge Q)$$
Converting Truth Tables to CNF
\begin{tabular}{cc|cc}
$P$ & $Q$ & $P \implies Q$ & $P \oplus Q$ \ \hline
\T & \T & \T & \F
\T & \F & \F & \T
\F & \T & \T & \T
\F & \F & \T & \F
\end{tabular}
The output of the operator is \T\ if and only if the inputs do not match any row where the output is \F. So, to get a CNF we can go over all the rows where hte output is \F, and for each write a clause that means we are not in that row. Then we AND all such clauses. For example, for $P \oplus Q$ we get
$$(\neg P \vee \neg Q) \wedge (P \vee Q)$$
The related 3CNF formulation
When we are only interested to know whether or not a given formula is satisfiable, we can write a 3CNF that is satisfiable iff the original formula is. In order to do that, we first write an equivalent CNF, and then convert it to a 3CNF (which is not necessarily equivalent, but only guarantees to preserve the satisfiability feature) as follow. For each clause with less than 3 literals such as $(A \lor \neg B)$ we add a dummy variable $C$ (only for this clause) and interprete the $(A \lor \neg B)$ as a formula over all of $A,B,C$ and write a CNF for them (which happens to be 3CNF!). For longer clauses such as $(A \lor B \lor C \lor D)$ we do another trick of breaking them into smaller parts using new dummy variables as follows $(A \lor B \lor \neg X) \wedge (\neg X \lor C \lor D).$